Math, asked by shifashafeeqms, 7 months ago

solve for real x a)4x+3<6x+7

Answers

Answered by vrajakumar35
2

Step-by-step explanation:

4x+3≤6x+7

⇒4x+3−3≤6x+7−3

⇒4x≤6x+4

⇒4x−6x≤6x+4−6x

⇒−2x≤4

⇒−x≤2

⇒x≥−2

∴x∈{−2,−1,0,1,2,...}

Answered by anurag2147
1

4x+3 < 6x+7

6x-4x < 3-7

2x < -4

x < -4/2

x< -2

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