Solve for sec x. If sec² x + ¾ sec x=½
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Step-by-step explanation:
Given that,
secx=
2
and
2
3π
<x<2π
secx=
2
=sec315
∘
∴x=315
∘
Now, tanx=tan315
∘
=−1
cotx=cot315
∘
=−1
cosecx=cosec315
∘
=−
2
1+cotx−cosecx
1+tanx+cosecx
=
1−1−(−
2
)
1−1−
2
=
2
−
2
=−1
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