Question

Solve for t-:
4Tt - 2t^2 = T^2

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Answer 1

The give equation is a quadratic equation in tt

Consider a quadratic equation;

ax2+bx+c=0ax2+bx+c=0

Solution for the variable xx is given by

x=−b±b2−4ac√2ax=−b±b2−4ac2a

Here

in t2−4Tt+2T2=0t2−4Tt+2T2=0

a=1,b=−4T,c=2T2a=1,b=−4T,c=2T2

Thus

t=−(−4T)±(−4T)2−4×1×2T2√2×1t=−(−4T)±(−4T)2−4×1×2T22×1

t=4