solve for θ: tanθ+tan2θ+tan3θ=tanθtan2θtan3θ
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tan(3theta)=tan(theta+2theta)=tan2theta+tantheta/1-tanthetaxtan2theta
multiply the denominator of rhs with lhs.
substitute what is in the question.
you will get tantheta+tan2theta=0
hence, tan3theta=0
so, 3theta=0,pie,2pie,.. or give the principal value.
multiply the denominator of rhs with lhs.
substitute what is in the question.
you will get tantheta+tan2theta=0
hence, tan3theta=0
so, 3theta=0,pie,2pie,.. or give the principal value.
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