solve for teeta tan 3 teeta =1/√3
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Answered by
0
Answer:
hope it's helpful to you
Answered by
1
Step-by-step explanation:
Correct option is
C
3
nπ
+
36
7π
(
tan3θ+1
tan3θ−1
)=(
1
3
)
usecomponendoanddividendo,weget
(
tan3θ−1−tan3θ−1
tan3θ−1+tan3θ+1
)=(
3
−1
3
+1
)ortan3θ=(
1−
3
3
+1
)
ortan3θ=(
1−tan(
3
π
)(
4
π
)
tan(
3
π
)+tan
4
π
)
∴3θ=(
3
π
)+(
4
π
)
∴θ=(
3
nπ
)+(
36
7π
)
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