Question

solve for thankyou plz answer

Answer 1

$let \: the \: time \: taken \: by \: one \: pipe \: be \: x \: minutes \: and \: the \: other \: be \: x + 3 \: minutes$

Answer 2

Answer:

Step-by-step explanation:

Let the volume of the cistern be V.

Together two pipes take 3 1/13 mins = 40/13

Rate of both the pipes together = V/(40/13)

Let pipes be A and B,

Time taken by A = t mins , So rate = V/t

Time taken by B = t+3 mins, So rate = V/(t+3)

Combined rate = V/t + V/(t+3)

We already know that combined rate = V/(40/13)

Equating both ,

V/t + V/(t+3) = V/(40/13)

1/t + 1/(t+3) = 13/40

(t+3+t) / t(t+3) = 13/40

(2t + 3)/ (t^2+3t) = 13/40

80t + 120 = 13t^2 + 39t

13t^2 - 41t - 120 = 0

The quadratic equation yields two roots :

5 and -1.846 , since time cannot be negative

Time taken by pipe A = 5 mins

Time taken by pipe B = 5+3 = 8 mins

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