solve for the 3rd question
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hope you will get it...
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let the unit digit of no.=x
let the tens digit of no.=9-x
no. will be=10(ten's digit)+unit digit
=10(9-x)+x=90-10x+x=90-9x
after interchanging digits:-
no. will become...10(x)+9-x=9x+9
according to question....
(9x+9)-(90-9x)=27
9x+9-90+9x=27
18x=108
x=108/18=6
hence no.=90-9(6)=90-54=36
hope u will understand......
mark as brainliest
let the tens digit of no.=9-x
no. will be=10(ten's digit)+unit digit
=10(9-x)+x=90-10x+x=90-9x
after interchanging digits:-
no. will become...10(x)+9-x=9x+9
according to question....
(9x+9)-(90-9x)=27
9x+9-90+9x=27
18x=108
x=108/18=6
hence no.=90-9(6)=90-54=36
hope u will understand......
mark as brainliest
shubhg:
Thanksgiving Answer
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