Math, asked by NidhraNair, 1 year ago

solve for the the given equation. find out x and y...

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Answered by Steph0303
2
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Hey!!
Here's your answer!!

x+y-8/2 = x+2y-14/3 = 3x+y-12/11

(x+y-8)/2……….(1)

(x+2y-14)/3………(2)

(3x+y-12)/11……..(3)

Take eq 1& 2

(x+y-8)/2= (x+2y-14)/3 
3(x+y-8)= 2(x+2y-14)

3x+3y-24= 2x+4y-28
3x-2x+3y-4y= -28+24
x-y= -4

x-y+4=0…………….(3)
Take eq 2 & 3

(x+2y-14)/3 = (3x+y-12)/11
11 (x+2y-14)= 3(3x+y-12)
11x+22y - 154= 9x+3y-36
11x -9x+22y-3y= -36+154
2x+19y= 118
2x+19y-118=0…………….(4)
Multiply equation (3) by 2  

2x-2y+8=0………..(5)
subtract equation (4) from eq (5)
2x-2y+8=0
2x+19y-118=0

(-)   (-)   (+)
_________________
-21y+126=0

-21y=-126

y= 126/21= 6
y= 6
From eq 3
x+y -8=0
x+6-8=0
x-2=0
x=2
Therefore, the values of x= 2 & y= 6
Hope this helps!!
Cheers!!

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NidhraNair: photography not clear
Steph0303: ok wait
Steph0303: fine??
NidhraNair: yes
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