Solve for the unknown measure.
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∆ABC and ∆DEF in, Ab=De, or Ac= df than bc=ef than now we find Ab walu , ab =ac +bc ab=15+20 ab=35
tha walu of AB =35
Now, ac =df ,ac=15 ,df=15 than ∆DEF ,ed=df+fe Ed=15+12 Ed =27 Now ∆Abc and ∆def , ab+bc+CA=35+20+15 ∆abc=70 , de+ef+fd=27+15+12 ∆def=54 Than ∆ABC and ∆DEF , ∆abc+∆def=180 70 +54 =180 124=180, =180-124 =64 answer =64 abc =\~def
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