Math, asked by balsicasj, 5 months ago

Solve for the value of x in x²-x=6

Answers

Answered by DEBOBROTABHATTACHARY
0

x²-x=6

=> x^2 - x - 6 =0

=> x^2 - 3x + 2x - 6 =0

=> x(x - 3) + 2(x - 3) =0

=> (x-3) (x+2) = 0

here , (x-3)= 0 or, (x+2) = 0

so,

=> x= (+3). or, x= (-2)

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