Solve for the value of x in x²-x=6
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x²-x=6
=> x^2 - x - 6 =0
=> x^2 - 3x + 2x - 6 =0
=> x(x - 3) + 2(x - 3) =0
=> (x-3) (x+2) = 0
here , (x-3)= 0 or, (x+2) = 0
so,
=> x= (+3). or, x= (-2)
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