Math, asked by Vvincelleanne, 10 hours ago

Solve for the value of x of x^4+8x^2+16=0. (I need at least two values of x)

Thank you for answering​

Answers

Answered by jaswasri2006
1

x⁴ = x² • x²

so,

(x² • x²) + 8x² + 16 = 0

when we split it , we obtain

2[x² + 8x² + 16] = 0

x² + 8x² + 16 = 0

9x² = -16

9x = √-16 = ±4

x = ±(4/9)

so , Values of x are

4/9 , -4/9

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