Question

solve for the value of x when the arithmetic mean of 5a-3 and 7a+7 is x ​

Answer 1

Answer:

$arithmetic \: \: \: mean \: \: \: = \: \: \: \frac{sum \: \: \: of \: \: the \: \: \: numbers \: \: \: }{total \: \: \: number \: \: \: of \: \: \: number } \\ \\ \\ x \: = \frac{(5a - 3) + (7a + 7)}{2} \\ \\ x = \frac{5a + 7a - 3 + 7}{2} \\ \\ x = \frac{12a + 4}{2} \\ \\ x = \frac{2(6a + 2)}{2} \\ \\ x = 6a + 2$

Answer 2

Answer:

arithmetic mean or A.M. is  = $\frac{(5a-3)+(7a+7)}{2}$ = $\frac{5a+7a+7-3}{2}=\frac{12a+4}{2}=\frac{6a+2}{1}=6a+2$

so $x=6a+2$

Step-by-step explanation: