Question

solve for the values of theta from 0-360 degrees for 2 sin theta (5 cos2theta+1)= 3sin 2theta

Answer 1

Answer:

cos2thetha+sin2thetha=cos2thetha

on putting this value in another equation we get

cos2thetha \: + {sin}^{2} thetha \: + {sin}^{2} thetha = 1cos2thetha+sin2thetha+sin2thetha=1

cos2thetha +2sin^2 theta =1

sin thetha =

\sqrt{ \frac{1 - cos2thetha}{2} }21−cos2thetha

similarly it is of cos theth