Question

Solve for the X in 4^x+6^x=9^x

Answer 1

here

divide every term by 9^x

(4/9)^x+(6/9)^x=1

(2/3)^(2x) +(2/3)^x=1

assume (2/3)^x=a

you'll get a quadratic

a²+a-1=0

use shree dharmacharya formula(the quadratic formula)

and then put the value of a

discard the negative answer

a=(-1+√5)/2

then take log on both sides