Question

Solve for theta, 4 sin squared theta -1 = 0, where theta is acute

Answer 1

Answer:

30°

Step-by-step explanation:

$4 { \sin}^{2} theta - 1 = 0 \\ {sin}^{2} theta = \frac{1}{4} \\ sin \: theta = \sqrt{ \frac{1}{4} } \\ sin \: theta = \frac{1}{2} \\ sin \: theta = sin30 \\ theta = 30$

Answer 2

Heya !

Let's draw ur equation first:-

$\implies$ 4sin²θ - 1 = 0

$\implies$ 4sin²θ = 1

$\implies$ Sin²θ = $\dfrac{1}{4}$

$\implies$ Sin²θ = √1/4

$\implies$ Sin²θ = $\dfrac{1}{2}$

We know that, Sin 30⁰ = $\dfrac{1}{2}$

hence, the value of θ = 30⁰