solve for theta cos²theta\cot²theta-cos²theta=3
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We know, cot²∅=cos²∅ / sin²∅
So,
cos²∅/cot²∅ - cos²∅
=(cos²∅ x sin²∅ / cos²∅ ) - cos²∅
=sin²∅ - cos²∅
= 1-cos²∅ - cos²∅
=1-2cos²∅ =3
It implies, 2cos²∅= -2
= cos²∅= -1
Which is not possible, so there exists no such value of ∅ for which the given equation is true.
So,
cos²∅/cot²∅ - cos²∅
=(cos²∅ x sin²∅ / cos²∅ ) - cos²∅
=sin²∅ - cos²∅
= 1-cos²∅ - cos²∅
=1-2cos²∅ =3
It implies, 2cos²∅= -2
= cos²∅= -1
Which is not possible, so there exists no such value of ∅ for which the given equation is true.
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