Solve for theta if theta is acute cos3theta (2sin 2theta - 1) = 0. Can you please show the working too thx
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cos3∅ (2sin 2∅ - 1) = 0
2sin 2∅ - 1 = 0
2sin 2∅ = 1
sin 2∅ = 1/2
We know that sin60° = 1/2
sin 2∅ = sin 60°
2∅ = 60°
∅ = 30°
So, the acute angle in 30°.
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