solve for U and V .... 2(3u-v)=5uv ; 2(u+3v) = 5uv
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Answered by
3
2(3u - v) =5uv
6u - 2v =5uv ……(1)
2(u+3v)=5uv
2u + 6 v =5uv …[2]
(2) ✖ 3 = 6 u + 18 v =15 uv …(3)
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(3)-(1)
6 u + 18 v =15 uv
6u - 2v =5uv
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20 v = 10 uv
20=10u
u =2
substitute 2(u+3v)=5uv
2( 2+3v) =5(2) v
4+6v =10v
4=4v
v = 1
Therefore, ( u, v) =(2,1)
Answered by
0
Step-by-step explanation:
6u-2v=5uv;2u+6v=5uv
by elimination,
4u-8v=0
4(u-2v)=0
u-2v=0
u=2v
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