Question

solve for unique solution​

Answer 1

Given simultaneous equations:

kx+2y = 3 => kx+2y-3=0

3x+6y = 10=> 3x+6y -10=0

Compare these equations

with a1x+b1y+c1 = 0 and

a2x+b2y+c2 = 0 , we get

a1=k , b1=2 , c1 = -3,

a2 = 3 , b2= 6 , c2 = -10

Here ,

a1/a2 ≠ b1/b2

[ Equations have unique

solution - given ]

=> a2/a1 ≠b2/b1

=> 3/k ≠ 6/2

=>(3×2 )/6 ≠ k

1 ≈ k

Therefore,

value of k = 1

••••

Answer 2

Answer:  k=1

Step-by-step explanation:

a1/a2=b1/b2.  

k/3=2/6

k=1