Question

Solve for unknown
(x+1)-(2x+4)/3-5x=1/23

Answer 1

this is the solution of your question

Answer 2

Hello!

$\dfrac{\sf (x+1)-(2x+4)}{\sf 3-5x} = \dfrac{1}{23} \\ \\ \implies \dfrac{\sf x+1-2x-4}{\sf 3-5x} = \dfrac{1}{23} \\ \\ \implies \dfrac{\sf -x-3}{\sf 3-5x} = \dfrac{1}{23} \\ \\ \implies \sf 3-5x = \sf -23x - 69 \\ \\ \implies \sf 23x - 5x = -69-3 \\ \\ \implies \sf 18x = -72 \\ \\ \implies \sf x = \dfrac{-72}{18} \implies \boxed{\red{\bf{x = -4}}}$

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