Question

solve for using laws of exponents
can you solve ?
[(3/7^3x × (3/7)^3] / (7/3)^-4 = (3/7)^2×(7/3)^-4x​

Answer 1

Answer:

= 9/49/7/3= 3/7^2*7/3^-4x

= 3/7^-4x = 1/1^2x

=3/7^-4x*1/1^2x

=3/7^-2

Step-by-step explanation:

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