Question

Solve for using quadratic formula
$\sqrt{7y {?}^{2} } - 6y - 13 \sqrt{7} = 0$
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Answer 1

Answer:

√7y2 – 13y + 7y — 13 √7 = 0 y (√7 y – 13) + √7 (√7 y – 13) = 0 (√7 y – 13) (y + √7) = 0 √7y – 13 = 0; y + √7 = 0 Read more on Sarthaks.com - https://www.sarthaks.com/936320/find-the-roots-of-the-following-quadratic-equations-by-factorisation-7y-2-6y-137-0