Solve for ; where 0° ≤ ≤ 90°
sin2 + cos
2 30° =
5
4
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Solyyyg
ve for ; where 0° ≤ ≤ 90°
sin2 + cos
2 30° =yh
5
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4
Write a article on working of tankless water heaters.... Around 200 words
100 points question
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3
Answer:
x°=45°
Step-by-step explanation:
sin^2 x° + cos^2 30° = 5/4
=> sin^2 x° + ( √3/2)^2 = 5/4
=> sin^2 x° = 5/4 - 3/4
=> sin^2 x° = 1/2
=> sin x° = 1/ √2
=> sin x° = sin 45°
=> x° = 45°
Hope it helped :)
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