Math, asked by jothihari13, 11 months ago

Solve for ; where 0° ≤ ≤ 90°
sin2 + cos
2 30° =
5
4

Answers

Answered by iftikharzafar5576
0

Solyyyg

ve for ; where 0° ≤ ≤ 90°

sin2 + cos

2 30° =yh

5

jkjjjtyy

4

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100 points question

Answered by chinmayeesolanki98
3

Answer:

x°=45°

Step-by-step explanation:

sin^2 x° + cos^2 30° = 5/4

=> sin^2 x° + ( √3/2)^2 = 5/4

=> sin^2 x° = 5/4 - 3/4

=> sin^2 x° = 1/2

=> sin x° = 1/ √2

=> sin x° = sin 45°

=> x° = 45°

Hope it helped :)

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