Solve for x: 0=5x^2+3x−1.
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The above given Equation 5x²+3x-1 is in the form of a quadratic equation e.g., ax²+bx+c .It can be solve through either middle term splitting method or by using quadratic formula:
Here,middle term splitting is not possible as there are no such factors found to be factorise.
Here ,we solve it by using Quadratic formula:
x= -b±√b²-4ac÷2a
5x²+3x-1
Here ,
a= 5,b= 3 & c= -1
➙x= -3±√3²-4(5)(-1)÷2(5)
➙x= -3±√9-(-20)/10
➙x= -3±√9+20/10
➙x= -3±√29/10
The discriminant b²-4ac is > 0
So,it have two real roots
➙x= -3±√29/10
➙x= -3/10±√29/10
➙x= 0.23 or x = -0.83
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➙x= -3±√29/10
➙x= -3/10±√29/10
➙x= 0.23 or x = -0.83
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