Math, asked by choopiechoopa, 4 months ago

Solve for x.

1. -2 + 4/5x = 6
2. 2.5 (x - 3) = -5
3. 5/6 (x + 4) = 15

Answers

Answered by SweetPrapti
1

Answer:

1. x=10

2. x =4/5

3. x= 14

Step-by-step explanation:

1. -2 + 4/5x = 6

4/5x=8

x=8*5/4

x=10

2. 2.5 (x - 3) = -5

25/10 x - 75/10 =-5

25/10 x =-50+75/10

25/10 x = 2

x= 4/5

3. 5/6 (x + 4) = 15

5/6 x+ 20/6=15

5/6x =90-20/6

5/6x= 70/6

x= 70/6*6/5

x=14

Answered by aryan073
2

Question :

Solve for x :

(1) -2+4/5x=6

(2) 2.5(x-3)=-5

(3)5/6(x+4)=15

To find :

the value of X in this equation =?

Solution :

 \large \green{ \bold{ \underline{step \: by \: step \: explaination : }}}

 \\  \bf \: (1) \:  - 2 +  \frac{4}{5} x = 6

  \\ \implies \tt \:  \:  -2 +  \frac{4}{5}x = 6

 \\  \implies \tt \:  - 10 + 4x = 30

 \\  \implies \tt \:  - 10 + 4x - 30 = 0

 \\  \implies \tt \:  - 40 + 4x = 0

  \\ \implies \tt \: 4x = 40 \: \:  \:  \:  ie \:  \: x =  \frac{40}{4}

 \\  \implies \tt \: x =  \cancel \frac{40}{4}  = 10 \:  \:

  \:  \:  \: \implies \boxed{ \tt { \underline{x = 10}}}

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 \\  \bf \: (2) \: 2.5(x - 3) = -  5

 \\  \implies \tt \: 2.5(x - 3) =  - 5

 \\  \implies \tt \: 2.5x - 7.5 =  - 5

  \\ \implies \tt \: 2.5x - 7.5 + 5 = 0

 \\  \implies \tt \: 2.5x  - 7.5 + 5.0 = 0

 \\  \implies \tt \: 2.5x = 2.5

 \\  \implies \tt \: x =  \frac{2.5}{2.5} = 1

 \:  \:  \:  \implies \boxed{ \tt{ \underline{x = 1}}}

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 \\  \bf \: (3) \frac{5}{6} (x + 4) = 15

  \\ \implies \tt \:  \frac{5}{6} (x + 4) = 15

  \\ \implies \tt \:  \frac{5}{6} x +  \frac{5 \times 2}{3}  = 15

  \\ \implies \tt \:  \frac{5}{6} x +  \frac{10}{3}  = 15

 \\  \implies \tt \:  \frac{5}{6}x +  \frac{10 \times 2}{3 \times 2}  = 15

 \\  \implies \tt \:  \frac{5}{6} x +  \frac{20}{6}  = 15

  \\ \implies \tt \:  \frac{5x + 20}{6}  = 15

 \\   \implies \tt \: 5x + 20 = 15 \times 6

 \\  \implies \tt \: 5x + 20 = 90

 \\  \implies \tt \: 5x = 90 - 20

  \\ \implies \tt \: 5x = 70 \:  \: ie \: x =  \frac{70}{5}

  \\ \implies \tt \: x =  \frac{70}{5}  = 14

 \:  \:  \:  \implies \boxed{ \tt{ \underline{x = 14}}}

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