Solve for x:
(1/a+b+x)=(1/a)+(1/b)+(1/x)
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Answered by
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HERE IS YOUR ANSWER. ....
(1/a+b+x)=(1/a)+(1/b)+(1/x)
(1/a+b+x) - (1/x) =(1/a)+(1/b)
(x - a -b-x) /x (a+b+x) = (a+b) / ab
-(a+b) / x (a+b+x) = (a+b) / ab
-1 / x (a+b+x) = 1/ab
BY CROSS MULTIPLICATION
-ab. = x (a+b+x)
x (a+b+x) +ab = 0
ax + xb + x^2. + ab = 0
x^2 + x (a+b) +ab =0
BY MID TERM SPLITTING
x^2 +ax + bx +ab =0
x (x+a) + b (x+a) =0
(x+a) (x+b ) =0
sope .. x =-a. x = -b
HOPE IT HELPS YOU! ! ! ! ! ! !
ALSO FOLLOW ME
(1/a+b+x)=(1/a)+(1/b)+(1/x)
(1/a+b+x) - (1/x) =(1/a)+(1/b)
(x - a -b-x) /x (a+b+x) = (a+b) / ab
-(a+b) / x (a+b+x) = (a+b) / ab
-1 / x (a+b+x) = 1/ab
BY CROSS MULTIPLICATION
-ab. = x (a+b+x)
x (a+b+x) +ab = 0
ax + xb + x^2. + ab = 0
x^2 + x (a+b) +ab =0
BY MID TERM SPLITTING
x^2 +ax + bx +ab =0
x (x+a) + b (x+a) =0
(x+a) (x+b ) =0
sope .. x =-a. x = -b
HOPE IT HELPS YOU! ! ! ! ! ! !
ALSO FOLLOW ME
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0
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