solve for x: (1/x+1)+(2/x+2)=(1/x+4),x≠1,-2,-4
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Consider x+11+x+22=x+44
That is, x+11=2[x+42−x+21]=2[(x+4)(x+2)2x+4−x−4]
x+21=2[(x+2)(x+4)x]
x2+6x+8=2x2+2x
Thus, we have x2−4x−8=0, which is a quadratic equation.
(The above equation can also be obtained by taking LCM )
Using the quadratic formula we get,
x=2(1)4±16−4(1)(−8)=24±48
Thus, x=2+23 or 2−23
Hence, the solution set is {2−23,2+23}
Step-by-step explanation:
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