Solve for x
1/(x-1)(x-2) + 1/(x-2)(x+3) + 1(x-3)(x-4) =1/6
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Answer:
7
Step-by-step explanation:
1/ (x-1) (x-2) +1/ (x-2) x-3) +1/ (x-3) (x-4) =1/6
(x-1)- (x-2) / (x-1) (x-2) +
(x-2)-(x-3) / (x-2) (x-3) +
(x-3)- (x-4) / (x-3) (x-4) =1/6
1/ (x-2)-1/ (x-1) +1/ (x-3)
-1/ (x-2) +1/ (x-4)-1/ (x-3) =1/6
1/ (x-4)-1 (x-1) =1/6
(X-1)- (x-4) / (x-1) (x-4) =1/6
3/ (x^2-5x+4) =1/6
x^2-5x+4=18
X^2-5x-14=0
(x-7) (x-2) =0
X=2; 7
But ifx=2 the 1/ (x-2) doesn't exist so x=7
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