Math, asked by ashafahad33, 2 months ago

solve for x
1/x-3+1/x-2= 8x​

Answers

Answered by Saby123
7

Solution :

1/(x-3) + 1/(x-2) = 8x

Taking LCM on LHS

> (x-3) + (x-2)/(x-3)(x-2) = 8x

> 2x - 5 = 8x( x-2)(x-3)

> 2x-5 = 8x(x^2-5x+6)

> 8x^3 - 40x^2 + 48x = 2x - 5

> 8x^3 - 40x^2 + 46x - 5=0

The roots of this cubic equation will be imaginary. Hence no real solution for x.

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Answered by HarshitJaiswal2534
0

Step-by-step explanation:

Solution :

1/(x-3) + 1/(x-2) = 8x

Taking LCM on LHS

> (x-3) + (x-2)/(x-3)(x-2) = 8x

> 2x - 5 = 8x( x-2)(x-3)

> 2x-5 = 8x(x^2-5x+6)

> 8x^3 - 40x^2 + 48x = 2x - 5

> 8x^3 - 40x^2 + 46x - 5=0

The roots of this cubic equation will be imaginary. Hence no real solution for x.

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