solve for x 10(x-4)+2(x-5)-5(x+6)=0
who ever answers this will get 100 point
Answers
Answered by
4
Answer:
Answer
x−3
x−2
+
x−5
x−4
=
3
10
⇒
(x−3)(x−5)
(x−2)(x−5)+(x−3)(x−4)
=
3
10
⇒
x
2
−8x+15
x
2
−7x+10+x
2
−7x+12
=
3
10
⇒
x
2
−8x+15
2x
2
−14x+22
=
3
10
⇒3(2x
2
−14x+22)=10(x
2
−8x+15)
⇒6x
2
−42x+66=10x
2
−80x+150
⇒10x
2
−80x+150−6x
2
+42x−66=0
⇒4x
2
−38x+84=0
⇒2x
2
−19x+42=0
⇒x=
2×2
19±
19
2
−4×2×42
⇒x=
4
19±
25
⇒x=
4
19±5
⇒x=
4
19+5
,
4
19−5
∴x=
4
24
,
4
14
∴x=6,
2
7
Step-by-step explanation:
and this is for 10 points
Answered by
1
Given:
We have given an equation which is as 10(x-4)+2(x-5)-5(x+6)=0.
To Find:
We have to simplify the given equation for the value of x?
Step-by-step explanation:
- We have given an algebric equation which is as follows
- 10(x-4)+2(x-5)-5(x+6)=0.
- For simplifying the given equation we need to know the rule of BODMAS which is used in the algebraic equations to solve them.
- The rule of BODMAS said that for simplifying the equation we will do the brackets simplification first of all then we proceeded to division
- First of all we are solving the brackets of the given equation by multiplying the terms
- Now, we take the like terms together and simplify them as
- Now we do the addition and subtraction in equation written above
Hence, the value of x is
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