Solve for x: 1000^x=625
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It will be done by log identities.
㏒ of both sides
㏒₁₀(1000^x) = ㏒₁₀(625)
x · ㏒₁₀(1000) = ㏒₁₀(625)
x = ㏒₁₀(625)/㏒₁₀(1000)
㏒ of both sides
㏒₁₀(1000^x) = ㏒₁₀(625)
x · ㏒₁₀(1000) = ㏒₁₀(625)
x = ㏒₁₀(625)/㏒₁₀(1000)
User019:
What are log identities?
and 1000^2 is 1,000,000
wait for 5 min
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