Solve for x: 12x² - 6(a² + b²)x + 3 a²b² = 0.
solve without quadratic formula
use
(b²–4ac)
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Step-by-step explanation:
12x^2-6(a^2+b^2)+3a^2b^2=0
factorise
12x^2-6a^2x-6b^2x-3a^2b^2=0
6x(2x-a^2)-3b^2(2x-a^2)=0
(6x-3b^2)(2x-a^2)=0
6x-3b^2=0,2x^2-a^2=0
x=b^2/2,x=a^2/2
pls mark my ans as brainiest
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