Question

solve for x: 12x²-6(a²+b²) x+3a²b²=0

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$12 {x}^{2} - 6( {a}^{2} + {b}^{2} )x + 3 {a }^{2} {b}^{2} = 0 \\ 12 {x}^{2} - 6 {a}^{2} x - 6 {b}^{2} x + 3 {a}^{2} {b}^{2} = 0 \\ 12 {x}^{2} - 12 {a}^{2} {b}^{2} {x}^{2} + 3 {a}^{2} {b}^{2} = 0 \\ 12 {x}^{2} - 12 {a}^{2} {b}^{2} + 3 {a}^{2} {b}^{2} = 0 \\ 12 {x}^{2} - 9 {a}^{2} {b}^{2} = 0$