Math, asked by chauhanarnav558, 4 months ago

.Solve for x : 13(x−4) − 3(x−9) − 5(x+4) = 0

Answers

Answered by Anonymous
2

Answer:

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Step-by-step explanation:

13(x-4)-3(x-9)-5(x+4) = 0

13x-52-3x+27-5x-20=0

13x-3x-5x-52+27-20=0

5x-45=0

5x=45

x=45/5

x=9

Answered by tennetiraj86
9

Step-by-step explanation:

Given:-

Given equation is 13(x−4) − 3(x−9) − 5(x+4) = 0

To find:-

.Solve for x : 13(x−4) − 3(x−9) − 5(x+4) = 0

Solution:-

Given equation is 13(x−4) − 3(x−9) − 5(x+4) = 0

=>13x - 52 -3x +27 - 5x -20 = 0

=>(13x - 3x - 5x) + (- 52 + 27 - 20) = 0

=>(13 - 3 - 5) x + ( - 72 + 27 ) = 0

=>(13 -8)x + ( -45) = 0

=>5x + (-45) = 0

=>5x - 45 = 0

=>5x = 45

=>x = 45/5

=>x= 9

The value of x = 9

Check:-

If x=9 then LHS = 13(x−4) − 3(x−9) − 5(x+4)

=>13( 9-4) -3(9-9) -5(9+4)

=>13(5)-3(0)-5(13)

=>65-0-65

=>65-65

=>0

=> RHS

LHS = RHS is true for x=9

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