CBSE BOARD X, asked by army94sam, 2 months ago

Solve for x: 16/x-1 = 15/x+1; x≠ 0,1​

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Answered by tarushi25
3

Answer:

The solution is x=±4

Step-by-step explanation:

Given the equation

\frac{16}{x}-1=\frac{15}{x+1}\text{, x is not equal to 0 or -1.}x16−1=x+115, x is not equal to 0 or -1.

we have to solve the above equation.

\frac{16}{x}-1=\frac{15}{x+1}x16−1=x+115

\frac{16-x}{x}=\frac{15}{x+1}x16−x=x+115

Cross multiplying both sides, we get

(16-x)(x+1)=15x(16−x)(x+1)=15x

16x+16-x^2-x=15x16x+16−x2−x=15x

16x-15x-x+16=x^216x−15x−x+16=x2

x^2=16x2=16

Taking square root on both sides, we get

x=\pm 4x=±4

HOPE IT WILL HELP:)

Answered by ankitanther98
2

Explanation:

16x+16 =15x-15

16x-15x =-15-16

x= -31

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