Math, asked by niteshbiswas13, 1 month ago

solve for x :
16/x -1 = 15/x +1 ; x = 0, -1​

Answers

Answered by MisSadaa007
5

Given the equation

\frac{16}{x}-1=\frac{15}{x+1}\text{, x is not equal to 0 or -1.}x16−1=x+115, x is not equal to 0 or -1.

we have to solve the above equation.

{16}{x}-1=\frac{15}{x+1}x16−1=x+115

\{16-x}{x}=\frac{15}{x+1}x16−x=x+115

Cross multiplying both sides, we get

(16-x)(x+1)=15x(16−x)(x+1)=15x

16x+16-x 2-x=15x16x+16−x2−x=15x

16x-15x-x+16=x 216x−15x−x+16=x2

x^2=16x2=16

Taking square root on both sides, we get

x=\pm 4x=±4

Answered by kritishpanda1
6

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