solve for x:2[2x-1/x+3]-3[x+3/2x-2]=6
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2(2x-1/x+3)-3(x+3/2x-1)=5
or, {2(2x-1)²-3(x+3)²}/(x+3)(2x-1)=5
or, {2(4x²-4x+1)-3(x²+6x+9)}/(2x²+6x-x-3)=5
or, 8x²-8x+2-3x²-18x-27=5(2x²+5x-3)
or, 5x²-26x-25=10x²+25x-15
or, 5x²-10x²-26x-25x-25+15=0
or, -5x²-51x-10=0
or, 5x²+50x+x+10=0
or, 5x(x+10)+1(x+10)=0
or, (x+10)(5x+1)=0
Either, x+10=0
or, x=-10
Or, 5x+1=0
or, 5x=-1
or, x=-1/5
∴, x=10,-1/5 Ans
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