solve for x, 2^3(5^0+3^2x) =224/27
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Answer:
2^3(5^0 + 3^2x) = 224/27
8(1 + 3^2x) = 224/27
(1 + 3^2x) = 28/27
3^2x = 28/27 - 1
3^2x = (28-27)/27 = 1/27
3^2x = 3^-3
2x = - 3
x = - 3/2
thank uh!!
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