Math, asked by chitrashanthi8889, 8 months ago

solve for x, 2^3(5^0+3^2x) =224/27

Answers

Answered by rutujagajhans
5

Answer:

2^3(5^0 + 3^2x) = 224/27

8(1 + 3^2x) = 224/27

(1 + 3^2x) = 28/27

3^2x = 28/27 - 1

3^2x = (28-27)/27 = 1/27

3^2x = 3^-3

2x = - 3

x = - 3/2

thank uh!!

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