Question

Solve for x: 2(3x + 4) - 3(x - 1) = x - 1 x =

Answer 1

Answer:

= 6x+8-3x+3=x-1x

= 3x+11=-x

= 3x+x=-11

= 4x=-11

= x=-11/4

Answer 2

Answer :-

$\sf2 \: (3x + 4) - 3 \: (x - 1) = x - 1$

On removing the brackets by multiplying the numbers,

$\sf6x + 8 - 3x + 3 = x - 1$

By putting the constants and variables separately using brackets,

$\sf(6x - 3x) + (8 + 3) = x - 1$

On simplifying,

$\sf3x + 11 = x - 1$

Transposing the constants in the RHS, leaving the variables in the LHS,

$\sf3x - x = - 1 - 11$

$\sf2x = - 12$

$\sf x = \dfrac{ - 12}{ \: \: \: \: \: 2}$

On dividing - 12 by 2,

$\sf x = - 6.$

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Steps to solve this equation :-

1) First open the brackets by multiplying the number outside the brackets with the number inside the brackets. (Like I multiplied 2 by 3x and 4)

2) Then put the variables and constants separately. You can use brackets (Its your choice)

3) Now simplify the numbers.

4) After that, bring the x from RHS to LHS and change its sign. Do the same with the number in LHS. (11)

5) Again simplify the numbers.

6) Now bring 2 from LHS to RHS and change its sign.

7) Now divide -12 by 2.

8) - 6 is the result obtained, which is the value of x.

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