solve for x;(✓2/5)^x+2
Answers
Answered by
1
Answer:
ohhhhhhhhhhhhhhhhhhhhhhhhh
Answered by
1
Answer:
2/x2 - 5/x + 2 = 0
⇒ 2 – 5x + 2x2/x2 = 0
⇒ 2x2 – 5x + 2 = 0
⇒ 2x2 – 4x – x + 2 = 0
⇒ 2x(x – 2) - 1(x - 2) = 0
⇒ (x – 2)(2x – 1) = 0
⇒ x – 2 = 0
Or 2x – 1 = 0
⇒ x = 2
or x = 1/2 are two roots of the equation.
Similar questions