Math, asked by laeeqhajeera4433, 6 months ago

Solve for x: (2 – 7x)/(1 – 5x) = (3 + 7x)/(4 +5x) ​

Answers

Answered by gitanjali4922
14

{{\fcolorbox{red}{white}{ \fcolorbox{red}{white}{ \bf{ \color{black}{solution \:  \:  \:  \:  \:  \:  \:\: \:\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}}}}}

\color{black}\bold</p><p>{ \frac{2 - 7x}{1 - 5x} =  \frac{3 + 7x}{4 + 5x}  }

\color{black}\bold</p><p>{ \mapsto \:(2 - 7x)(4 + 5x) = (3 + 7x)(1 - 5x }

\color{black}\bold</p><p>{ \mapsto \: 8 + 10x - 28x - 35 {x}^{2}  = 3 - 15x + 7x - 35 {x}^{2} }

\color{black}\bold</p><p>{ \mapsto \: - 35 {x}^{2}  + 35  {x}^{2}  + 10x - 28x + 15x - 7x = 3 - 8 }

\color{black}\bold</p><p>{ \mapsto \: 10x - 28x + 15x - 7x =  - 5}

\color{black}\bold</p><p>{ \mapsto \:10x + 15x - 28x - 7x =  - 5 }

\color{black}\bold</p><p>{ \mapsto \:25x - 35x  =  - 5}

\color{black}\bold</p><p>{ \mapsto \: - 10x =  - 5 }

\color{black}\bold</p><p>{ \mapsto \:x =  \frac{ - 5}{ - 10}  }

\color{black}\bold</p><p>{ \mapsto \:x =  \frac{1}{2}  }

{ \boxed{∵x =  \frac{1}{2} }}</p><p>

{{\fcolorbox{red}{white}{ \fcolorbox{red}{white}{ \bf{ \color{black}{ \:  \:  \:  \:  \:  \: verification \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}}}}}

\color{black}\bold</p><p>{ LHS =  \frac{2 - 7x}{1 - 5x}  }

\color{black}\bold</p><p>{  =  \frac{2 - 7 \times  \frac{1}{2} }{1 - 5 \times  \frac{1}{2} }  }

\color{black}\bold</p><p>{   = 2 - 7 \times  \frac{1}{2} \div 1 - 5 \times  \frac{1}{2}  }

\color{black}\bold</p><p>{ = 2 -  \frac{7}{2}   } \div 1 -  \frac{5}{2}

\color{black}\bold</p><p>{   =  \frac{4 - 7}{2} \div  } \frac{2 - 5}{2}

\color{black}\bold</p><p>{  =  \frac{ - 3}{2}  \div  \frac{ - 3}{2}  }

\color{black}\bold</p><p>{  =  \frac{ - 3}{2}  \times  \frac{2}{ - 3}  }

\color{black}\bold</p><p>{   = 1}

\color{black}\bold</p><p>{  RHS =  \frac{3 + 7x}{4 + 5x} }

 \color{black}\bold{ =  \frac{3 + 7 \times  \frac{1}{2} }{4 + 5 \times  \frac{1}{2} } }

 \color{black}\bold{ = 3 + 7 \times  \frac{1}{2} \div 4 + 5 \times  \frac{1}{2}  }

\color{black}\bold{ =3 +  \frac{7}{2}  \div 4 +  \frac{5}{2}   }

\color{black}\bold{ =  \frac{6 + 7}{2} \div   \frac{8 + 5}{2} }

\color{black}\bold{ =  \frac{13}{2}  \div  \frac{13}{2} }

\color{black}\bold{ =  \frac{13}{2} \times  \frac{2}{13}  }

\color{black}\bold{ = 1}

{ \boxed{∵verified }}</p><p>

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