solve for x: 2(x-1)(x^2-2x+3)(x^2-2x-3)/x(x-2) <=0
Answers
Answered by
2
Step-by-step explanation:
Given that,
(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0
⇒x
2
+2x+3x+6+x
2
−3x−2x+6−2x
2
−2x=0
⇒2x
2
−2x
2
+5x−5x−2x+12=0
⇒−2x+12=0
⇒−2x=−12
⇒x=6
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Answered by
0
Step-by-step explanation:
Given that,
(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0
⇒x
2
+2x+3x+6+x
2
−3x−2x+6−2x
2
−2x=0
⇒2x
2
−2x
2
+5x−5x−2x+12=0
⇒−2x+12=0
⇒−2x=−12
⇒x=6
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