Math, asked by sreekala3174, 7 months ago

solve for x: 2(x-1)(x^2-2x+3)(x^2-2x-3)/x(x-2) <=0​

Answers

Answered by AayushNigade
2

Step-by-step explanation:

Given that,

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x

2

+2x+3x+6+x

2

−3x−2x+6−2x

2

−2x=0

⇒2x

2

−2x

2

+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6

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Answered by sreenath4345
0

Step-by-step explanation:

Given that,

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x

2

+2x+3x+6+x

2

−3x−2x+6−2x

2

−2x=0

⇒2x

2

−2x

2

+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6

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