Math, asked by rizazainab7, 1 month ago

solve for x: (2^x+3)^1/2=16​

Answers

Answered by deepakkumar8022
0

Answer:

x:(22^x+3)^1/2=16

x/(2x+3)^1/2=16

squaring both side

x^2=256(2x+3)

x^2=512x+768

x^2-512x-768=0

x^2-32x-24x-768=0

(x-32)(x-24)=0

x=24,32

Answered by itzsecretagent
3

Answer:

x:(22^x+3)^1/2=16

→x/(2x+3) 1/2=16

squaring both side

x^2=256(2x+3)

→x^2=512x+768

→x^2-512x-7683D0

→X^2-32x-24x-7683D0

→(X-32)(x-24)=0

→x=24,32

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