solve for x: (2^x+3)^1/2=16
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Answered by
0
Answer:
x:(22^x+3)^1/2=16
x/(2x+3)^1/2=16
squaring both side
x^2=256(2x+3)
x^2=512x+768
x^2-512x-768=0
x^2-32x-24x-768=0
(x-32)(x-24)=0
x=24,32
Answered by
3
Answer:
x:(22^x+3)^1/2=16
→x/(2x+3) 1/2=16
squaring both side
x^2=256(2x+3)
→x^2=512x+768
→x^2-512x-7683D0
→X^2-32x-24x-7683D0
→(X-32)(x-24)=0
→x=24,32
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