Question

solve for x 2 X by x minus 5 whole square + 2 X by X - 5 - 24 = 0 where X is not equal to 5 ​

Answer 1

Answer:

$x = 4 \\ \\ or \\ \\ x = 15$

Step-by-step explanation:

I think your question must be

${ \bigg( \frac{2x}{x - 5} \bigg) }^{2} + \frac{10x}{x - 5} - 24= 0$

$\frac{4 {x}^{2} }{ {(x - 5)}^{2} } + \frac{10x}{(x - 5)} - 24 = 0 \\ \\ \frac{4 {x}^{2} + 10x(x - 5) - 24( {x - 5)}^{2} }{( {x - 5)}^{2} } = 0 \\ \\ 4 {x}^{2} + 10x(x - 5) - 24( {x - 5)}^{2} = 0 \times ( {x - 5)}^{2} \\ \\ 2(2 {x}^{2} + 5 {x}^{2} - 25x - 12( {x - 5)}^{2} ) = 0 \\ \\ 7{x}^{2} - 25x - 12 {x}^{2} + 120x - 300 = 0 \\ \\ - 5 {x}^{2} + 95x - 300 = 0 \\ \\ {x}^{2} - 19x + 60 = 0 \\ \\ {x}^{2} - 15x - 4x + 60 = 0 \\ \\ x(x - 15) - 4(x - 15) = 0 \\ \\ (x - 15)(x - 4) = 0 \\ \\ x = 15 \\ \\ or \\ x = 4$

Hope it helps you.