Question

solve for x 2 x square plus ax minus a square =0​

Answer 1

Answer:

x = -a, a/2

Step-by-step explanation:

$2 {x}^{2} + ax - {a}^{2} = 0 \\ = > 2 {x}^{2} + 2ax - ax - {a}^{2} = 0 \\ = > 2x(x + a) - a(x + a) = 0 \\ = > (2x - a)(x + a) = 0 \\ \\ for \: (x + a) = 0 \\ = > x = - a \\ \\ for \: (2x - a) = 0 \\ = > 2x = a \\ = > x = \frac{a}{2}$