Solve : for ‘x’ (27/64)^2x+4= (256/81 )^3x−6
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Step-by-step explanation:
let X be n due to my mobile but u write in the place of n X only
(27/64)²ⁿ+⁴=(256/81)³ⁿ-⁶
{(3/4)³}²ⁿ+⁴={(4/3)⁴}³ⁿ-⁶
(3/4)⁶ⁿ+¹²=(4/3)¹²ⁿ-²⁴
(3/4)⁶ⁿ+¹²=(3/4)^-(12n-24)
6n+12=-12n+24
6n+12n=24-12
18n=12
n=12/18
n=2/3
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