Solve : for ‘x’ (27/64)^2x+4= (256/81 )^3x−6
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Answer:
(-2/7)-4 × (-5/7)2
= (7/-2)4 × (-5/7)2
= (-7/2)4 × (-5/7)2 [Since, (7/-2) = (-7/2)]
= (-7)4/24 × (-5)2/72
= {74 × (-5)2}/{24 × 72 } [Since, (-7)4 = 74]
= {72 × (-5)2 }/24
= [49 × (-5) × (-5)]/16
= 1225/16
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