Solve for x:
2log x + 1 = log 250
Answers
Answered by
3
Given that :
2logx + 1 = log250
=> logx² + log10 = log250
( mlogn = logn^m & log10 = 1)
=> log(10×x²) = log250 (logmn = logm + logn)
=> 10x² = 250
=> x² = 25
=> x = 5
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Answered by
3
Step-by-step explanation:
assuming that base of log is 10
therefore 1 can be written as log 10
also using property of log--> m*log n= log n^m
hence above equation can be reduced to
log x² + log 10 = log 250
by another property of log --.> log m + log n = log m*n
log{10x²} = log250
by taking exponent function both sides (removing log function)
10x²=250
x²= 25
x=±5
hence x have two values +2 and -2.
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