Question

solve for x 2sinx square -3sinx+1=0​

Answer 1

Answer:

x = π/2 or π/6, 5π/6 (in radians)

x = 90° or 30°, 150°

Step-by-step explanation:

$2 { \sin}^{2}(x) - 3 \sin(x) + 1 = 0 \\ let \: sin(x) = u \\ = > 2 {u}^{2} - 3u + 1 = 0 \\ using \: quadratic \: formula \\ = > u = \frac{3± \sqrt{ {3}^{2} - 4 \times 2 \times 1 } }{4} \\ = > u = \frac{3±1}{4} \\ = > u = 1 \: or \: \frac{1}{2} \\ \\ \sin(x) = 1 \: or \: \frac{1}{2} \\ = > x = \frac{\pi}{2} \: or \: \frac{\pi}{6} , \: \frac{5}{6} \pi$