Question

solve for X
2x^2 - 40x + 200 = 0​

Answer 1

2x^2-20x-20x+200

2x(x-10)-20(x-10)

(x-10)(2x-20)

For value of x:

x-10 = 0

x = 10

2x-20 = 0

2x = 20

x = 20/2

x = 10

Hence, the value of x = 10

❣️Thnx dear.....!!❣️

Answer 2

$\huge \mathfrak \pink </p><p>{solution:-}$

$<font color= " red">$

$2x^2-40x+200 =0$

$=>2x (x-10) -20(x-10)$

$=> (x-10) (2x-20)$

$<font color= " blue">$

$\huge value. of..X= ?$

$X-10=0$

$\huge \red X=10.$

$<marquee>♥mark as brainliest..✌♥</marquee>$